If triangle ABC, right angled at C, then the value of sec (A+B) =
a)0
b) 1
c) 2/√3
d) not defined
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Answered by
1
Answer:
d
Step-by-step explanation:
sum of the angles
A+B+C=180
A+B=180-C
=180-90 (since it is right angled at c)
=90
Now
sec(A+B)=sec90=not defined
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