Question

if triangle ABC similar to triangle pqr and areas of two similar triangle are 64 CM square and 121 CM square respectively if Q R equals to 15 cm find the side BC

Answer 1

given:area triangle ABC =64 cm and and area PQR =120 cm
then:since both triangles are similar
so,64/121=(BC/QR)^2
64/121=(BC/15)^2
8/11=BC/15
BC=8×15/11=10.909cm

Answer 2

Answer:

Step-by-step explanation:

It is given that triangle ABC is similar to triangle PQR and areas of two similar triangle $64cm^2$ and$121cm^2$ respectively.

Therefore, using the area similarity conduition, we have

$\frac{arABC}{arPQR}=(\frac{BC}{QR})^{2}$

$\frac{64}{121}=(\frac{BC}{15})^{2}$

$\frac{8}{11}=\frac{BC}{15}$

$BC=\frac{8{\times}15}{11}$

$BC=10.909cm$

Thus, the measure of the side BC is 10.909 cm.