Question

if triangle and ar of triangle abc by ar of triangle qrp =9/4 and bc = 15 cm find pr

Answer 1

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Area of ∆ ABCArea of ∆QRP = 94

AB = 18 cm , BC = 15 cm So PR = ?

We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides.

Area of ∆ ABCArea of ∆ QRP = AB2QR2 = BC2PR2 = AC2QP2

So , we take  

Area of ∆ ABCArea of ∆ QRP = BC2PR2

Now substitute all given values and get

94 = 152PR2

Taking square root on both hand side , we get

32 = 15PR

PR = 10 cm

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