Question

if triangle PQR is similar to traingle XYZ , angle Q =50degree and angle R =70degree ,then fine angle X+angle Y ?
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Answer 1

Answer:

<X + <y = 110°

Step-by-step explanation:

In ∆PQR and ∆XYZ

PQ=XY

QR=YZ

RP = ZX

By SSS congruence

∆PQR =~ ∆XYZ

By CPCT,

<Q = <Y

50° = <Y

<R = <Y

70° = <Y

In ∆PQR

<P + <Q + <R = 180°

<P = 60° = <X

<X + <Y = 60° + 50°

=110°

I hope this might help u

Answer 2

Answer: 110°

Step-by-step explanation: ∆PQR is ~ ∆XYZ. <Q=<Y= 50°; <R= <Z= 70°. Hence <P = <X= 180-(50+70)= 60°. Angle sum property.

Angle X + Angle Y= 60+50= 110°