If triangle pqr ~ triangle xyz , angle q = 50° and angle r =70° , then angle x + angle y =?
Answers
Answered by
45
angle sum property
50+70+p= 180
180- 120 = 60 = p
x= 60
y= 50
z = 70
x + y
60 + 50 = 110
50+70+p= 180
180- 120 = 60 = p
x= 60
y= 50
z = 70
x + y
60 + 50 = 110
Answered by
1
Answer:
We get that ∠X + ∠Y is equal to 110°.
Step-by-step explanation:
We have:
ΔPQR ~ Δ XYZ
Also,
∠Q = 50°
∠ R = 70°
We know that according to angle sum property of triangle,
∠P + ∠ Q + ∠R = 180°
∠P + 50° + 70° = 180°
∠P = 180° - 120°
∠P = 60°
Since the triangles are similar, we get using the AAA rule that:
∠X = 60°
∠Y = 50°
Substituting the values, we get that:
∠X + ∠Y = 60° + 50°
∠X + ∠Y = 110°
Therefore, we get that ∠X + ∠Y is equal to 110°.
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