If triangleABC corresponding trianglePQR,then A(AABC)
A -
A (A POR)=ABsquare upon....... =........upon QRsquare
All
= =
N al 9R2
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Step-by-step explanation:
Given: AABC ~ APQR ZABC = ZP QR (Corresponding angles)
Now, AD and PM are altitudes of AABC and
APQR respectively,
thus, in AABD and AP QM
ZABD ZP QM (Since, AABC APQR)
ZADB = ZPMQ (Each 90°)
ZBAD ZQPM (Third angle)
Thus, AABD APQM (AAA rule)
Hence,
AB AD
PQ PM
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