Math, asked by gowdarachana56, 6 hours ago

)If triangles ABC and DEF are similar and AB = 4 cm, DE= 6 cm, EF = 9 cm and

FD = 12 cm, the perimeter of triangle ABC is:

A) 22 B) 20

C) 21 D) 18 ​

Answers

Answered by andrewjackson7291
3

Answer:

perimeter =18 cm

Step-by-step explanation:

since both triangles are similar so sides are in proportion so

AB/BC=DE/EF

BC/AC=EF/FD

by this 6,8 cm respectively answer comes

perimeter=AB+BC+AC =18 cm

Answered by nityadasari10
3

Answer:

Perimeter of triangle ABC is 18cm.

Step-by-step explanation:

Given

triangle abc = triangle def

Then

AB/ED = BC/EF = AC/DF

4/6 = BC/9 = AC/12

By, taking first two terms

4/6 = BC/9

BC = 4×9/6

= 36/6 = 6 cm

AC = 6×12/9

= 72/9 = 8 cm

Therefore,

perimeter of triangle ABC = AB + BC + CA

= 4 + 6 + 8 = 18 cm

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