Math, asked by babitakumari8793, 2 months ago

If TWO^2 = THREE where the alphabets are single digit integers then find T + W + O​

Answers

Answered by BarnoCoodle
0

Answer:

downstairs

Step-by-step explanation:

Given : TWO² = THREE where the alphabets are single-digit integers

To Find : T + W + O

Solution:

TWO² = THREE

alphabets are single-digit integers

TWO is three digit numbers

and THREE is 5 digit numbers

Hence T must be 1

T = 1

Now trying different possible combination

TWO are different digits

Hence can be 102 , 103 , 104 , 105 , 106 , 107 , 108 , 109 , 120 , 123 , 124 , 125 , 126 , 127 , 128 , 129 , 130 , 132 , 134 , 135 , 136 , 137 , 138 , 139 , 140

142² is 6 digit number

number ending with 0 are not possible as then O = 0 and E = 0

Hence only 138² = 19044 end with repeated digit

T = 1 W = 3 , O = 8

H = 9 , R = 0 , E = 4

T + W + O = 1 + 3 + 8 = 12

T + W + O = 12

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