if two angles of quadrilateral are equal and third angle is 70°.find other three angles.
A=x
B=?
C=70°
D=x
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Sum of all four angles of quadrilateral = 360
So,
Angle A + angle c + angle D = 360
X + 70 + X = 360
2x+ 70 = 360
2x= 360 - 70
2x= 310
X = 2/310
X = 155
Therefore, x = 155
B = 155
2x = 2( 155) 310
2x = 2(155)310
This is the sum
So,
Angle A + angle c + angle D = 360
X + 70 + X = 360
2x+ 70 = 360
2x= 360 - 70
2x= 310
X = 2/310
X = 155
Therefore, x = 155
B = 155
2x = 2( 155) 310
2x = 2(155)310
This is the sum
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0
Answer:
sorry I also don't know this answer..
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