Question

If two balanced dice are rolled what is the probability that sum of the integers coming on the upper side of the dice is 9

Answer 1

probability of event is 4 {(3,6)(6,3)(5,4)(4,5)}
total no. of event=36
P(e) =4/36 0r 1/9
hope it helps u

Answer 2

Question :- If two balanced dice are tossed once, what is the probability of the event that the sum of the integers coming on the upper sides of the two dice is 9 ?

Solution :-

we know that, when two dice are tossed once, then possible events will be

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

Total 36 .

so,

→ Total possible events where sum of upper side of the dice is 9 is = (3,6), (4,5), (5,4) and (6,3) = Total 4 .

therefore,

→ Required Probability = Favourable outcomes / Total number of outcomes = 4/36 = (1/9) (Ans.)

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