Question

If two bodies of different masses m, and m, are
dropped from different heights h, and h two, then ratio
of the times taken by the two to drop through these
distances is :
(A) h:h two
B)h two/h
(C) √h:√h two
(D) h²:h two²​

Answer 1

For a freely falling object :

a=g;

Initial velocity=u=0 m/s

g=9.8m/s²

from second equation of motion:S=ut+1/2 at²

for First object we get :

h1= gT1²/2

⇒T1=√2h1/g

For second object we get h2=gT2²/2

⇒T2=√2h2/g

T1/T2 =√h1/h2

But here h1= a and h2 =b

so, T1/T2=√a/b

Answer 2

Answer:

i think c is correct answer