If two boys pull the cart in opposite direction with a force of 100 N
Answers
Answer:
Following Newton's third law (... equal and opposite forces...), the string stretches until it reaches its tightest point.
You might imagine this to be like a tug-of-war game with both sides dead even.
Since we are focusing on horizontal forces, and since exactly two horizontal forces are pulling in opposite vector directions to the same extent, these cancel each other out, as seen here:
∑
F
x
=
T
−
F
x
=
m
a
x
=
0
As stated in the question, it would mean that
T
=
F
x
(so
T
−
F
x
=
0
). Thus, if
F
x
=
10 N
,
T
=
10 N
.
(Additionally, even if
m
is small,
a
x
must therefore be
0 m/s
2
.)
Answer:Resultant force is nothing but the total force acting on a body including their directions. If the object is at rest or it moves with a same velocity, the resultant force should be zero. All forces are acting on same direction, resultant force should be the sum of all the forces.
In this case, two boys exert forces of 40N and 60N in opposite directions on an object. This means that one force goes with a plus sign and the other force goes with the minus sign.
That is, F
R
=F
1
−F
2
=60N−40N=20N.
Hence, a force of 20 N acts in the direction of greater force.
Explanation: