If two capacitors of capacitace 4nf nd 2nf are connected in series find the effective capacitance of the കോമ്പിനേഷ
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Answer:
4/3nf
Explanation:
Effective Capacitance (in series) : 1/C = 1/C1 + 1/C2 + 1/C3 + 1/C4........
Here C1 = 4nf
C2= 2nf
1/C = 1/4 + 1/2
= (1+2)/4
= 3/4
Therefore C = 4/3nf
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