Question

If two charges of -5uc and +5uc are separated by 5cm. find electrostatic force.

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Answer 1

$\huge{\underline{\underline{\red{\mathfrak{AnSwEr :}}}}}$

Given :

• First Charge (Q1) = -5 μC
• Second Charge = 5 μC
• Distance (d) = 5 m

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To Find :

• Electrostatic Force

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Solution :

Convert charges to C from μC

${\rm{Q_1 \: = \: -5 \: \times \: 10^{-6}C}} \\ \\ {\rm{Q_2 \: = \: 5 \: \times \: 10^{-6}C}}$

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Now use Coloumb's law :

$\huge{\boxed{\sf{F \: = \: k \dfrac{Q_1 Q_2}{d^2}}}} \\ \\ \implies {\sf{F \: = \: k \dfrac{-5 \: \times \: 10^{-6} \: \times \: 5 \: \times \: 10^{-6}}{(5)^2}}} \\ \\ \implies {\sf{F \: = \: k \dfrac{-25 \: \times \: 10^{-12}}{25}}} \\ \\ \implies {\sf{F \: = \: - k \: \times \: 10^{-12}}} \\ \\ \implies {\sf{F \: = \: -(9 \: \times \: 10^{9}) \: \times \: 10^{-12}}} \\ \\ \implies {\sf{F \: = \: -9 \: \times \: 10^{-3}}} \\ \\ \implies {\sf{F \: = \: -9 \: mN}} \\ \\ {\underline{\sf{\therefore \: Electrostatic \: force \: is \: -9 \: mN}}}$

Answer 2

$\large \bigstar\boxed{\bf \red{ GIVEN}} \bigstar \\ \\ \Longrightarrow \bf{q}_{1} = - 5 \mu C = - 5 \times {10}^{ - 6} C \\ \\\Longrightarrow \bf{q}_{2} = 5 \mu C = 5 \times {10}^{ - 6} C \\ \\ \Longrightarrow \bf d = 5 \: m$

$\large \bigstar\boxed{\bf \red{ TO \: FIND}} \bigstar \\ \\ \bf \Longrightarrow Electrstatic \: Force$

$\large \bigstar\boxed{\bf \red{ SOLUTION}} \bigstar \\ \\ \large \boxed{ \bf \green{ F = k \frac{ {q}_{1} {q}_{1}}{ {d}^{2} }} } \\ \\ \Longrightarrow \bf F= k \frac{ - 5 \times {10}^{ - 6} \times 5 \times {10}^{ - 6} }{ {5}^{2} } \\ \\ \Longrightarrow \bf F= k \frac{ - 25 \times {10}^{ - 12} }{25} \\ \\\Longrightarrow \bf F = - k \times {10}^{ - 12} \\ \\ \boxed{\bf k = 9 \times {10}^{9}} \\ \\\Longrightarrow \bf F = - 9 \times {10}^{9} \times {10}^{ - 12} \\ \\ \Longrightarrow \bf F = - 9 \times {10}^{ - 9} \\ \\ \large \boxed{\bf \orange{ F = - 9\:Nm} }$