if two circles intersect at two points prove that their centres lie in the perpendicular bisector of the common chord
explain properly with figure
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A AB is the common chord of the two circles and OO' is the line segment joining the centres of the two circles. Let OO' intersect AB at P. To prove: OO' is the perpendicular bisector of AB. Hence, OO' is the perpendicular bisector of AB.
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