Question

if two coins are tossed find the probability of getting at least 1head

Answer 1

E = tossing two coins = 4

A = getting at least one head = 3

P(A) = A/E = 3/4

Answer 2

S=(HH,HT,TT,TH)

n(S)=4

Let A be the event of getting atleast one head.

A=(HH,HT,TH}

n(A)=3

Probability of event A

p(A)=n(A)/n(S)

=3/4