Question

If two coins are tossed, find the probability of the following events:

(i) Getting at least one head

(ii) Getting no head​

Answer 1

Answer:

Step-by-step explanation:

hey user here is your answer..

2 coins .

head head

head tail

tail head

tail tail.

i) 3/4

ii) 1-3/4

=1/4

hope it helps !!..

:)

Answer 2

Step-by-step explanation:

HEY MATE.........

$s = (hh) \: (ht) \: (th) \:( tt) \\ \\ n(s) = 4 \\ \\ let \: a \: be \: the \: event \: of \: getting \: at \: least \: one \: head \: \\ \\ a = (ht )\:( th )\:( hh) \\ \\ n(a) = 3 \\ \\ p(a) = \frac{n(a)}{n(s)} = \\ \\ p(a) = \frac{3}{4} \\ \\ 2.) \: let \: b \: be \: the \: event \: of \: getting \: no \: head \: \\ \\ b = (tt) \\ \\ n(b) = 1 \\ p(b) = \frac{n(b)}{n(s)} = \frac{1}{4} \\ \\ p(a) = \frac{3}{4} \: \: p(b) = \frac{1}{4}$

HOPE IT HELPS YOU