If two copper wires A and B of length 1 m and 2 m with their cross section area of 10 and 5 cm sqr what will be the ratio of their specific resistance?
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here is your answer
Ra==rho×L1/A1=rho×1/1/10=10rho
Rb==rho×L2/A2=2rho/1/20=40rho
there fore
Ra/Rb==10rho/40rho=1:4
answer.....
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