Question

If two diagonals of a rhombus are of lengths 240m and 44m then find the height and the perimeter of the rhombus

Answer 1

As we know, the diagonals of rhombus bisect eachother at 90° so each diagonal form 2 parts

120m , 120m , 22m , 22m.

using Pythagoras theorem ,

(120)^2 + (22)^2 = x ^2

so x = 122m.= Lenght

All sides of rhombus are same so perimeter would be 4*122 = 488m^2

Hope it helps!