Math, asked by rohit1195, 8 months ago

If two different numbers are randomly selected from the first 10 natural numbers, what is the probability that the sum of the selected numbers will be 11.

Answers

Answered by Anonymous
0

Step-by-step explanation:

If you can pick the same number twice, there are 10 numbers to pick from for the second number and exactly one of those will yield a sum of 11. So 1/10 chance (10%).

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Answered by thebalachowdary
1

Answer:

1/9

Step-by-step explanation:

We can look at this a different way. It doesn't matter what the first number is. Whatever it is, there is exactly one number we can pick for the second number that will make the sum equal 11. For 5 that number is 6, for 10 that number is 1, for 3 that number is 8, etc.

So assuming you can’t pick the same number twice, after we pick the first number we are left with 9 numbers to pick from where one of those will result in the sum being 11. So 1/9 chance (11.1%).

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