Question

if two electric charges of 5 microcoulomb and 10 microcoulomb are placed 20cm apart in a medium of dielectric constant 5. then electrostatic force between them is what??

Answer 1

Explanation:

The electrostatic force between charges placed at a distance d is

q1q2/4Πek r^2

q1=5x10^-6

q2= 10x10^-6

d= 20x10^-2

1/4πe = 9x10^9

solve the problem by substituting above values

then we get 2.5x10^-10=2.5A°