Question

If two equal chord of a circle intersect within the circle, prove that the line joining the point of intersection to the centre makes equal angle with the chord (answers the question please​

Answer 1

Answer:

In △OMX and △ONX,

∠OMX=∠ONX=90°

OX=OX(common)

OM=ON [where AB and CD are equal chords and equal chords are equidistant from the centre.]

△OMX≅△ONX by RHS congruence rule.

∴∠OXM=∠OXN

i.e.,∠OXA=∠OXD

Hence proved.