Question

If two equal chords of a circle intersect within the circle, prove that the line
joining the point of intersection to the centre makes equal angles with the chords
​

Answer 1

Answer:

hope this will help you

Answer 2

Answer:

For the diagram REFER THE ATTACHMENT

Step-by-step explanation:

Given:

Let AB &CD be two equal chords intersecting at point X

To Prove:

OX makes equal angles with the chord i,e, ∠OXA = ∠OXD

Proof:

Draw OM ⊥ AB & ON ⊥ CD

In ∆OMX and ∆ONX

∠OMX = ∠ONX [Each 90°]

OX = XO [Common]

OM = ON [AB and CD are equal chords and equidistant from centre]

By RHS(Right Angle ,Hypotenuse, Side) criteria

∆OMX ≈ ∆ONX

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@#Mark as Brainliest