If two equal chords of a circle intersect within the circle, prove that segments of one chord are equal to corresponding segments of other chord
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Answer:
Given: Let AB & CD be the two equal chords intersecting at point X.
A
⇒ AB = CD
M
B
To prove: Corresponding segments are equal, i.e.,
AX = DX
and
BX = CX
D
Proof: We draw OM LAB & ON 1 CD
So, AM = BM == AB
& DN = CN = / CD
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