If two forces are in the ratio 8:9act on two areas in the ratio10:3,find the ratio of pressure exerted?
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The two forces will be 8 and 9
The area is also 10 and 3
Now the pressure will be
P=f+f/a+a=8+9/10+
17/13
So the pressure is 17:13
The area is also 10 and 3
Now the pressure will be
P=f+f/a+a=8+9/10+
17/13
So the pressure is 17:13
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