Question

If two gram atom of A react with 2 gram molecule of B4 according to following reaction
2A2 +3B4 +---- 4c
How A2 will be the limiting reagent

Answer 1

Answer:

From the balanced equation for the reaction we can find that

4 atoms of A require 3 gram molecules of B4

Therefore 2 atoms of require=2×3÷4 =6÷4 =1.5

But we have 2 gram molecule of B4 in a place where 1.5 is only needed B4 is in excess and the reaction is stopped only by the limitation of A2, therefore A2 is the limiting reagent.