If two linked genes a & b shows 20% recombination (cross over), the ratio of gametes produced by F1 hybrids of
++/+ + x ab/ab is
(A) ++ 80% : ab 20%
(B)
++ 50% : ab 50%
(C) ++ 40% : ab 40% : + a 10% : + 10%
(D) ++ 30% : ab 30% : + a 20% : +b 20%
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Answer:
Explanation:
The combined linkage frequency between the parental combinations ++ and ab is 80%
The combined recombination frequency between the recombinant combination +a and +b is 20%
The individual frequencies would be half of the combined.
So, the correct option is ' ++40 : ab40 : +a10 : +b10'.
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