If two natural numbers are multiplied, they give a number which is their LCM.
Write two conclusive statements from this
Subject :- Maths
Anonymous:
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Answers
Answered by
103
Hey there!
Let the numbers be a, b.
Given that,
Product of numbers = LCM.
a * b = LCM.
Now, Let this be the equation of reference.
We know that,
Product of numbers = LCM * HCF
So, a * b = LCM * HCF
a * b = a * b * HCF from equation of reference
HCF = 1 .
So , One conclusive statement is the HCF of numbers is 1 .
We know that, When two numbers have HCF or GCD = 1 , they are co-primes .
So, Other conclusive statement is They are co primes.
=================================
Now, If two numbers are multiplied, they give result as LCM ,
From this statement,
The following conclusive statements can be made :
1) The numbers are Co-primes.
2) The number have 1 as Highest common factor
Let the numbers be a, b.
Given that,
Product of numbers = LCM.
a * b = LCM.
Now, Let this be the equation of reference.
We know that,
Product of numbers = LCM * HCF
So, a * b = LCM * HCF
a * b = a * b * HCF from equation of reference
HCF = 1 .
So , One conclusive statement is the HCF of numbers is 1 .
We know that, When two numbers have HCF or GCD = 1 , they are co-primes .
So, Other conclusive statement is They are co primes.
=================================
Now, If two numbers are multiplied, they give result as LCM ,
From this statement,
The following conclusive statements can be made :
1) The numbers are Co-primes.
2) The number have 1 as Highest common factor
Answered by
150
let two number => X and Y ,
now , if we multiply , we get
X*Y = >. their HCF ( GCD ) * their LCM .
now , look the example =>
5* 4 => their { HCF } * their { LCM }
20 = 20 * 1
=> now , if we require to find , LCM
we can go through this mathod => X* Y / HCF => LCM
theirfor ,. 20 /1 => 20 .
here from EXAMPLE we get => X*Y => LCM
i.e => 20 =20 .
hence , the LCM = Product of two numbers / HCF ..
or simply , LCM => Product of two numbers
hope now it's clear !!!
thanks , for nice question !!
now , if we multiply , we get
X*Y = >. their HCF ( GCD ) * their LCM .
now , look the example =>
5* 4 => their { HCF } * their { LCM }
20 = 20 * 1
=> now , if we require to find , LCM
we can go through this mathod => X* Y / HCF => LCM
theirfor ,. 20 /1 => 20 .
here from EXAMPLE we get => X*Y => LCM
i.e => 20 =20 .
hence , the LCM = Product of two numbers / HCF ..
or simply , LCM => Product of two numbers
hope now it's clear !!!
thanks , for nice question !!
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