Question

If two numbers A and B are respectively 10% and 25% more than than the third number C , what percent is the fist number of second ??
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Answer 1

Answer:

Let the Number C be 100.

$\underline{\bigstar\:\textsf{Number A :}}$

$:\implies\tt A = C \times (100+10)\%\\\\\\:\implies\tt A =100 \times \dfrac{110}{100}\\\\\\:\implies\tt A = 110$

$\rule{140}{1}$

$\underline{\bigstar\:\textsf{Number B :}}$

$:\implies\tt B = C \times (100+25)\%\\\\\\:\implies\tt B =100 \times \dfrac{125}{100}\\\\\\:\implies\tt B = 125$

$\rule{180}{2}$

Let the Percent be x.

$\dashrightarrow\tt\:\:A =x\%\:of\:B\\\\\\\dashrightarrow\tt\:\:110 = \dfrac{x}{100} \times 125\\\\\\\dashrightarrow\tt\:\:110 = \dfrac{x}{4} \times5\\\\\\\dashrightarrow\tt\:\:x = \dfrac{110 \times 4}{5}\\\\\\\dashrightarrow\:\:\underline{\boxed{\red{\tt x = 88\%}}}$

⠀

$\therefore\:\underline{\textsf{Required Percentage will be \textbf{88\%}}.}$

Answer 2

$\huge{ \purple{ \bigstar{ \mathfrak{answer♡</p><p>}}}}$

$\huge{ \red{ \ddot{ \smile}}}$

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=>let the number be x

$\huge\boxed{ \red{ \mathfrak{solution}}} = >$

For Number A

A=C×(100+10)%

$\large \: A = 100 \times \frac{110}{100} \\ \\ { \boxed{ \purple{ A = 110}}}$

for Number B,

B=C×(100+25)%

$\large \: B = 100 \times \frac{125}{100} \\ \\ \boxed{ \green{B = 125}}$

let p=percent

A=p%of B

$110 = \frac{p}{100} \times 125 \\ \\ = > 110 = \frac{p}{4} \times 5 \\ \\ = > p = \frac{110 \times 4}{5} \\ \\ { \huge{ \boxed{ \pink{= > p = 85 }}}}$

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hops this may help you

$\huge{ \red{ \ddot{ \smile}}}$

$\huge \blue{ \mathfrak{thanks♡</p><p>}}$