Math, asked by hibamir1234, 2 months ago

If two numbers have a sum of 12 and twice the first greater than four times the second, what are the numbers?

Answers

Answered by sudhir1381kumar
0

Answer:

x+y=-1

2x+4y=-10

Let’s start with the first:

x+y=-1

You can solve for x or y, it doesn’t matter.

x=-1-y

Now, plug this into the second equation:

2(-1-y)+4y=-10

Distribute:

-2–2y+4y=-10

Now simplify:

-2+2y=-10

2y=-8

y=-4

Now, plug this one into the first, as that will be easier to compute.

x+y=-1

x-4=-1

x=3

So, the first number, x, is 3, and the second number, y, is -4

Step-by-step explanation:

x+y=-1

2x+4y=-10

Let’s start with the first:

x+y=-1

You can solve for x or y, it doesn’t matter.

x=-1-y

Now, plug this into the second equation:

2(-1-y)+4y=-10

Distribute:

-2–2y+4y=-10

Now simplify:

-2+2y=-10

2y=-8

y=-4

Now, plug this one into the first, as that will be easier to compute.

x+y=-1

x-4=-1

x=3

So, the first number, x, is 3, and the second number, y, is -4

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