if two numbers multiple is 588 and HCM is 7 then which is the smaller number
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We are told that the greatest common factor of two integers is 49. So, these integers are and , for some positive integers and . Notice that and must not share any common factor but 1, because if they do then GCF of and will be more that 49.
Next, we know that --> --> since and don't share any common factor but 1 then (x, y) can be only (1, 11) and (5, 7) (all other pairs (2, 10), (3, 9), (4, 8), (6, 6) do share common factor greater than 1). So, there are only two pairs of such numbers possible: 49*1=49 and 49*11=539 AND 49*5=245 and 49*7=343.
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