Question

If two of the zeroes of the polynomial x4 +3x3–7x2–27x –18 are –1 and –2 find the other zeroes

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

dividend x4 - 3x3 - 7x2 + 27x - 18

- divisor. * x3 x4 - 3x3

remainder - 7x2 + 27x - 18

- divisor * 0x2

remainder - 7x2 + 27x - 18

- divisor * -7x1 - 7x2 + 21x

remainder 6x - 18

- divisor * 6x0 6x - 18

remainder 0

Quotient : x3-7x+6 Remainder: 0