If two opposite angles of a parallelogram are (63-3x) degree and (4x-7) degree. find all the angles of the parallelogram
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Answered by
1
Hi friend
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Your answer
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Two opposite angles of a parallelogram = (63 - 3x)° and (4x - 7)° .
We know that, opposite angles of a parallelogram are equal.
So,
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63 - 3x = 4x - 7
=> 63 + 7 = 4x + 3x
=> 7x = 70
=> x = 70/7
=> x = 10
Then,
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One of the angle = (4x - 7)° = (4 × 10 - 7)° = (40 - 7)° = 33°
It's adjacent angle = (180 - 33)° = 147°
Therefore,
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The angles of the parallelogram are 147°,33°,147° and 33°.
HOPE IT HELPS
--------------
Your answer
-------------------
Two opposite angles of a parallelogram = (63 - 3x)° and (4x - 7)° .
We know that, opposite angles of a parallelogram are equal.
So,
--------
63 - 3x = 4x - 7
=> 63 + 7 = 4x + 3x
=> 7x = 70
=> x = 70/7
=> x = 10
Then,
---------
One of the angle = (4x - 7)° = (4 × 10 - 7)° = (40 - 7)° = 33°
It's adjacent angle = (180 - 33)° = 147°
Therefore,
------------------
The angles of the parallelogram are 147°,33°,147° and 33°.
HOPE IT HELPS
Answered by
0
63 -3x =4x-7
63+7=4x+3x
70 =7x
x=10.
4x-7=4 (10)-7=33degree it's adjacent angle is 180-33 =147degree.
63+7=4x+3x
70 =7x
x=10.
4x-7=4 (10)-7=33degree it's adjacent angle is 180-33 =147degree.
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