Math, asked by raiudu40, 1 year ago

If two opposite angles of a parallelogram are (63-3x) degree and (4x-7) degree. find all the angles of the parallelogram

Answers

Answered by ArchitectSethRollins
1
Hi friend
--------------
Your answer
-------------------

Two opposite angles of a parallelogram = (63 - 3x)° and (4x - 7)° .

We know that, opposite angles of a parallelogram are equal.

So,
--------

63 - 3x = 4x - 7

=> 63 + 7 = 4x + 3x

=> 7x = 70

=> x = 70/7

=> x = 10

Then,
---------

One of the angle = (4x - 7)° = (4 × 10 - 7)° = (40 - 7)° = 33°

It's adjacent angle = (180 - 33)° = 147°

Therefore,
------------------

The angles of the parallelogram are 147°,33°,147° and 33°.

HOPE IT HELPS


Answered by Anonymous
0
63 -3x =4x-7
63+7=4x+3x
70 =7x
x=10.

4x-7=4 (10)-7=33degree it's adjacent angle is 180-33 =147degree.
Similar questions