Question

Two masses m and M are attached to strings as shown

Answer 1

Answer:

tan θ = 1+(2M+m)/2

Explanation:

at point p1:

2T1sin45° =mg

T1=T2=mg\Г2

At pt p2:

T3 sinθ=Mg+T2sin45°=g(2M+m)/2. -1eq

T3cosθ=T1cos45°=mg/2. -2eq

On dividing eq1 and eq2

tan θ=1+2M/m