Math, asked by ks6730150, 1 year ago

if two opposite angles of a parralelogram are(63-3x)degree and(4x-7)degree.find all the angles of the parralellogram
?

Answers

Answered by siddhu4972
0
63-3x=4x-7



63 +7=4x+3x
70=7x
70/7=X
X=7
63-3x=63-3×7
63-21
42

4x-7=4×7-7
28-7
21
Attachments:

Antan007: You gotta be kidding me
siddhu4972: sry worng ans
Antan007: 70/7=7
Antan007: Wrong spelling,
Answered by Antan007
0

Answer:


Step-by-step explanation:

We know that opposite angles of a parallelogram are equal

According to the problem,

(63-3x)°=(4x-7)°

=> 63°+7°=4x+3x

=>70°=7x

=>x=10°

Therefore opposite angles are

63°-3(10)°=33° {Let this angle be A of a parallelogram ABCD}

&

4(10)°-7°=33° {Let this angle be C of a parallelogram ABCD}

So angle B = (180-33)°=147°{ Adjacent angles of a parallelogram sum up to 180°}

angle B= angle D= 147°{ Opposite angles of a parallelogram are equal}

Hence in a parallelogram ABCD,

Angle A=33°

B=147°

C=33°

D=147°

Similar questions