if two opposite angles of a parralelogram are(63-3x)degree and(4x-7)degree.find all the angles of the parralellogram
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63-3x=4x-7
63 +7=4x+3x
70=7x
70/7=X
X=7
63-3x=63-3×7
63-21
42
4x-7=4×7-7
28-7
21
63 +7=4x+3x
70=7x
70/7=X
X=7
63-3x=63-3×7
63-21
42
4x-7=4×7-7
28-7
21
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Antan007:
You gotta be kidding me
Answered by
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Answer:
Step-by-step explanation:
We know that opposite angles of a parallelogram are equal
According to the problem,
(63-3x)°=(4x-7)°
=> 63°+7°=4x+3x
=>70°=7x
=>x=10°
Therefore opposite angles are
63°-3(10)°=33° {Let this angle be A of a parallelogram ABCD}
&
4(10)°-7°=33° {Let this angle be C of a parallelogram ABCD}
So angle B = (180-33)°=147°{ Adjacent angles of a parallelogram sum up to 180°}
angle B= angle D= 147°{ Opposite angles of a parallelogram are equal}
Hence in a parallelogram ABCD,
Angle A=33°
B=147°
C=33°
D=147°
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