Question

If two particles begin to fall freely from the same height but the second particle falls 2 seconds after the first

Answer 1

Answer:

Hey.

What we have to do in this question.

Tell me.

Thank you.

Answer 2

Answer:

$(d) \: 24.5m$

Explanation:

$time \: for \: {1}^{st} \: ball = 2 \: seconds$

$time \: for \: {2}^{nd} \: ball = 2 + 1 = 3 \: seconds$

$S_{1} = \frac{1}{2} g( {2}^{2} ) \: and \: S_{2} = \frac{1}{2} g( {3}^{2} )$

$S_{2} - S_{1} = g / 2(9 - 4) = 4.9 \times 5 = 24.5m$

$hence \: \: verified$