If two poles 5m and 15 m are 100m apart then find the height of poont of intersection of the line joining the otop of each pole
Answers
Answered by
0
Solution :-
Assuming that 5 m high pole is at the origin and the 15 m high pole is at x = 100 m
Then, the line from the base of the 5 m pole to the top of 15 m high pole is
⇒ y = 15x/100 ..........(1)
The line from the base of 15 m high pole to the top of 5 m high is
⇒ y = - 5x/100 + 5 ............(2)
Equating these two equations.
⇒ 15x/100 = - 5x/100 + 5
⇒ 0.15x = - 0.05x + 5
⇒ 0.15x + 0.05x = 5
⇒ 0.2x = 5
⇒ x = 5/0.2
⇒ x = 25
Putting the value of x = 25 in (1).
⇒ y = 15x/100
⇒ y = (15*25)/100
⇒ y = 375/100
⇒ y = 3.75 m
So, height of point of intersection is 3.75 m
Answer.
Assuming that 5 m high pole is at the origin and the 15 m high pole is at x = 100 m
Then, the line from the base of the 5 m pole to the top of 15 m high pole is
⇒ y = 15x/100 ..........(1)
The line from the base of 15 m high pole to the top of 5 m high is
⇒ y = - 5x/100 + 5 ............(2)
Equating these two equations.
⇒ 15x/100 = - 5x/100 + 5
⇒ 0.15x = - 0.05x + 5
⇒ 0.15x + 0.05x = 5
⇒ 0.2x = 5
⇒ x = 5/0.2
⇒ x = 25
Putting the value of x = 25 in (1).
⇒ y = 15x/100
⇒ y = (15*25)/100
⇒ y = 375/100
⇒ y = 3.75 m
So, height of point of intersection is 3.75 m
Answer.
Similar questions