Question

if two poles of height 10m and 15m stand vertically on a plane ground if the distance between their feet is 5root3m, find the distance between their tops

Answer 1

Please see the attached file.

Answer 2

Answer:

The distance between their tops is 10 m

Step-by-step explanation:

Refer the attached figure

Height of tower AB = 10 m

Height of tower CD = 15 m

The distance between their feet i.e. BD = 5√3 m

AB = ED = 10 m

CD = CE+ED

15 = CE +10

CE = 15-10 = 5

AE= BD = 5√3 m

In ΔACE

$Hypotenuse^2 = Perpendicular^2+Base^2$

$AC^2 = CE^2+AE^2$

$AC^2 = 5^2+(5\sqrt{3})^2$

$AC= \sqrt{5^2+(5\sqrt{3})^2}$

$AC= 10$

Hence  the distance between their tops is 10 m.