Math, asked by VishalNegi7653, 10 months ago

If two position integer a and b are written as a=x3y2 and b=xy2 find the hcf of a and b

Answers

Answered by has42000
0

Answer:

Step-by-step explanation:

a = x³y² = x * x * x * y * y

b = xy²  = x * y * y

HCF (a, b) = x * y * y = xy²

Answered by mhanifa
0

Answer:

xy²  

Step-by-step explanation:

Given: a=x³y² and b=xy²  

HCF of a and b is equal to b as b is divisor of both a and b:

HCF(a,b)= xy²

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