Math, asked by sauravabcd14, 1 year ago

if two positive integers p and q are written as p= a^2 b^3 and q= a^3 b; a, b are prime numbers, then verify: LCM (p, q) x HCF (p, q) = pq

Answers

Answered by nikitasingh79
22
HCF of two or more numbers is the product of the smallest power of each common prime factors involved in the numbers.

LCM of two or more numbers is a product of the greatest power of its prime factors involved in the numbers with highest power.


SOLUTION:

Given:

p = a²b³

q= a³b

HCF(p,q)= a²b

LCM (p,q)= a³b³

HCF× LCM= a²b× a³b³= a^5b⁴

HCF× LCM=a^5b⁴...........(1)

p ×q= a²b³× a³b= a^5b⁴

p ×q= = a^5b⁴..................(2)

Lcm (p,q) × Hcf(p,q) = pq

a^5b⁴ = a^5b⁴
[From equation 1 and 2]

Verified,..

Hope this will help you....
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