Question

if two resistance of 2ohm and 4ohm are connected in parallel connection then the equivalent resistance will be?

Answer 1

if two resistance of 2 ohm and 4 ohm are connected in parallel connection then the resistance, 1/Rp=1/2+1/4
1/Rp=(2+1)/4
1/Rp=3/4
Rp=4/3=1.34ohm.

Answer 2

Answer:

The equivalent resistance is 1.33Ω.

Explanation:

Given:

$R_{1}$ = 2Ω

$R_{2}$ = 4Ω

Here,

The first resistance is denoted by $R_{1}$.

The second resistance two is denoted by $R_{2}$.

The equivalent resistance of the resistances $R_{1}$ and $R_{2}$ is denoted by $R_{eq}$.

Now,

The resistances $R_{1}$ and $R_{2}$ are connected in parallel connection,

Then,

By the equation,

$\frac{1}{R_{eq}}=\frac{1}{R_{1}} +\frac{1}{R_{2}} \\\frac{1}{R_{eq}} =\frac{1}{2} +\frac{1}{4}$

$R_{eq}$ =  1.33Ω

So, if the two resistances 2Ω and 4Ω are connected in parallel connection then the equivalent resistance will be 1.33Ω.