Question

if two resistors R1 = 10 ohm an article 40 ohm are connected in parallel in a circuit of 12 volt battery then what will be the equivalent resistance of the circuit find the heat evolved in the circuit transfer 30 minutes ​

Answer 1

Answer:

Explanation:

r1= 10 ohm

r2=40 ohm

v= 12 V

1/Rp= 1/r1 + 1/r2

= 1/10 + 1/40

= 40+10/400

=50/400 = 1/8

Rp= 8 ohm

H= IVT

I= P/V

=12/8

= 1.5 A

H= 12*30

=360 J

Answer 2

540J.

Explanation:

• The two resistors R1 and R2 = 10 and 40 ohm.

• Combine resistance = 1 / RP = 1/ R1 + 1/ R2

1/ RP = 1/ 10 + 1/ 40

RP = 8 ohm.

• The heat can be calculated as follows:

H = V²/ R × t

H = 12 × 12 × 30 / 8

• 540J.

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