Question

if two roots of a quadratic equation are -2 and 3,determine the equation by showing the steps

Answer 1

Answer:

x= -2  , x =3

x(x-3)+2(x-3)=0

x2-3x+2x-6=0

x2-x-6=0

Step-by-step explanation:

Answer 2

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Here is your answer
If roots of the equation are 3 and -2

Sum of roots = 3+(-2)
= 3-2
=1

Product of roots = 3×(-2)
= -6

The equation is
${x}^{2} -(sum \: of \: roots)x + product \: of \: roots = 0 \\ {x}^{2} - 1x + ( - 6) = 0 \\ {x}^{2} - x - 6 = 0$

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