If two roots of quadratic equation
5x²+2x-3=0 are a and B, them let
determine the value of, a³+b³
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1
Answer:
5x^2+2x-3=0
5x^2+5x-3x-3=0
5x(x+1)-3(x+1)=0
(5x-3)(x+1)=0
x={-1,3/5}
let a= -1 b= 3/5
a^3+b^3 = (-1)^3+(3/5)^3
= -1+27/125 = (-125+27)/125
= -98/125
therefore a^3+b^3 = -98/125
Answered by
0
Answer:
therefore a³+ b³=-98/125
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