Question

if two sides of a rectangle are 4 and 3 meters then find the diagonal of rectangle​

Answer 1

Answer:

$as \: we \: know \: that \\ (diagonal) {}^{} = \sqrt{ {(leaght)}^{2} + {(breadth)}^{2} } \\ d = \sqrt{ {l}^{2} + {b}^{2} } \\ = \sqrt{ {4}^{2} + {3}^{2} } \\ = \sqrt{16 + 9 } = \sqrt{25 } \\ \sqrt{5 {}^{2} } = 5 \\ diagonal \: of \: this \: rectangle \: is \: 5 \: m$

Answer 2

Answer: 5

Step by step explanation:

Let L be length and breath be B.

L² + B² = D²

BTP,

4² + 3² = D²

=> (4×4) + (3×3) = D²

=> 16 + 9 = D²

=>25 = D²

=>D = 25 squareroot

=>D = 5

Ans: Diagonal is 5