Question

if two slips of paper are drawn from hat containing four slips labelled with 7,8,9,10.what is the probability of obtaining 7and then 9(the first slip is replaced before drawing the second slip).explain the answer

Answer 1

For the first draw you can draw 4 different slips, you can draw 7, or 8 or 9 or 10. But only one of those 4 is what you want. So the probability of the first draw being 7 is

P(1) = 1/4

Now for the second draw. When the first slip is replaced (regardless of what it was in the first draw), we again have 4 different slips either of which we can draw, but we only want 9. So the probability of the second draw being 9 is

P(2) = 1/4

Now let's define some events.

Event 1 is drawing the slip labelled 7 in the first draw.

Event 2 is drawing the slip labelled 9 in the second draw.

We want both of the events to happen.
So we want Event 1 AND Event 2

To find the probability of a composite event like the one above, we look at the word connecting the individual events......if it's AND, we multiply them and if it's an OR we add them.

Here it's an AND so we multiply the probabilities.

P =(1/4)×(1/4)

P = (1/16) = 0.0625

Answer 2

Answer:

Step-by-step explanation:

On