If two slit in youngs double slit experiment have width ratio 4:1 deduce the ratio of maxima and minima in interference pattern
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Answered by
1
yes then what we find here
Answered by
0
Intensity is proportional to width of the slit. thus,
I
2
I
1
=
25
1
or
a
2
a
1
=
I
2
I
1
=
5
1
or a
2
=5a
1
now,
I
min
I
max
=
(a
1
−a
2
)
2
(a
1
+a
2
)
=
(a
1
−5a
2
2(a 1 +5a 1 ) 2 =36/16=9/4
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