if two tangents are inclined at an angle of 60 degree of a circle with radius 6 cm and the length of each tangent is
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The length of each tangent is 13√3 cm.
Let PA and PB be two tangents to a circle O and radius 13 cm.
We are given ∠APB = 60°
We know that two tangents drawn to a circle from an external point are equally inclined to the segment joining the center to the point.
∴ ∠APO = ∠BPO = 1/2 × ∠APB = 1/2 × 60° = 30°
Also, OA ⊥ AP and OB ⊥ BP (radius ⊥ tangent at point of contact)
In right ΔOAP,
tan 30° = 13/PA
⇒ 1/√3 = 13/PA
⇒ PA = 13√3 cm.
∴ PA = PB = 13√3 cm. (Length of tangents drawn from an external point to the circle are equal).
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