Question

If two tangents inclined at an angle of 60 are drawn to circle of radius 13cm , then length of each tangent is equal to:

Answer 1

Given : Two tangents PA and PB are drawn external at Point P, OA=13cm and angle P=60°
To prove that :PA=PB=?
contrution : Join OP
proof : In Δ OAP
angle P=30°(hence the angle P is divided by angle bisector on joining Point's OP) and OA=13cm
using tan ratio
tanΦ=P/B
tan30°=OA/AP
1/√3=13/AP
1×AP=13×√3
AP=13√3cm
As the tangents drawn from external are equal so the length of each tangent =13√3cm
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Answer 2

Answer:

Step-by-step explanation:

Given : Two tangents PA and PB are drawn external at Point P, OA=13cm and angle P=60°

To prove that :PA=PB=?

contrution : Join OP

proof : In Δ OAP

angle P=30°(hence the angle P is divided by angle bisector on joining Point's OP) and OA=13cm

using tan ratio

tanΦ=P/B

tan30°=OA/AP

1/√3=13/AP

1×AP=13×√3

AP=13√3cm

As the tangents drawn from external are equal so the length of each tangent =13√3cm

I hope this will help you mark me as brainlest

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