Question

If two, three and four cuts are made parallel to different face a cube, then what is the number of identical pieces obtained?

Answer 1

Since there are two, three, and four cuts are made on the cube parallel to different face of a cube.

If we have 'L' number of cuts along the length , 'B' number of cuts along the breadth and 'H' number of cuts along the height.

Then the number of pieces along these dimensions will be $(L+1) \times (B+1) \times (H+1)$.

Since, we have 2 cuts along the length, 3 cuts along the width and 4 cuts along the height.

So, the number of identical pieces obtained  = $(2+1) \times (3+1) \times (4+1)$

= $3 \times 4 \times 5$

= 60

So, 60 identical pieces are obtained.

Answer 2

Answer:

60

Step-by-step explanation:

So let us take

a=2,b=3,c=4

Total identical pieces = (a+1)(b+1)(c+1)

= (2+1)(3+1)(4+1)

= (3)(4)(5)

=60